cos(2x)+10sin^2(x)=7

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Solution for cos(2x)+10sin^2(x)=7 equation:


Simplifying
cos(2x) + 10sin2(x) = 7

Remove parenthesis around (2x)
cos * 2x + 10sin2(x) = 7

Reorder the terms for easier multiplication:
2cos * x + 10sin2(x) = 7

Multiply cos * x
2cosx + 10sin2(x) = 7

Multiply in2s * x
2cosx + 10in2sx = 7

Solving
2cosx + 10in2sx = 7

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10in2sx' to each side of the equation.
2cosx + 10in2sx + -10in2sx = 7 + -10in2sx

Combine like terms: 10in2sx + -10in2sx = 0
2cosx + 0 = 7 + -10in2sx
2cosx = 7 + -10in2sx

Divide each side by '2osx'.
c = 3.5o-1s-1x-1 + -5in2o-1

Simplifying
c = 3.5o-1s-1x-1 + -5in2o-1

Reorder the terms:
c = -5in2o-1 + 3.5o-1s-1x-1

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